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I'm trying to understand the code here
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View: https://www.youtube.com/watch?v=NLKQEOgBAnw&t=443s

I don't understand this notation:
(x&(1<<i)) != 0

I understand we want to AND the bit at i position with 1, and see if it's equal to 1. So i assume that's what the formula is doing. Is this C code?
& must mean AND
i must be the position, 6 in the example: (x&(1 << 6)) != 0. Correct?
What's x?
What's <<? Does it mean "get the digit at position i"?
Why don't we say = 1 instead of != 0?
It’s testing the ith bit. Returns true if the ith bit is 1

Eg suppose x is 00001000 and I is 3
The 1 is 00000001
1<<3 is 00001000
X is. 00001000
AND is 00001000. Which is != 0, so the result is. True

Now suppose I = 2
1<<2 is 00000100
X is. 00001000
AND is 00000000. Which is not != 0, so the result is. False

(Examples show x as a byte, but it’s probably an int with a lot more leading 0 bits - doesn’t change the logic)

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