JavaScript How do I multiply even and uneven numbers inside an array using an loop

[Developsom]

Hello everyone,

First of all; I have been coding since February now so as you can understand im a real beginner.

* For a school assignment I have to use a loop to multiply all the even and uneven numbers inside an array.
* The script must work even if the array contains a trillion numbers.

Down here you can see the script that I have written so far.
My small knowledge mind tells me that the script is complete and correct apart from the '///' lines.
However, nothing could be less true and maybe the problem lies somewhere else.
I have tried multiple ways since yesterday to add the multipliers into the '////' lines but nothing seems to work 🙁

Really, I don't want to get emotional or anything out here right but honestly my brain hurts. Can someone release me of this pain ?

const numbers = [2, 4, 5, 29, 38];
for (let i = 0; i < numbers.length; i++) {
    if (i % 2 === 0) {
////---->MULTIPLY X2<------
    } if ( i % 2 !== 0) {
////---->MULTIPLY X3<------
    }
}
console.log(numbers)

This is one of my best tries.

const numbers = [2, 4, 5, 29, 38];
for (let i = 0; i < numbers.length; i++) {
    if (i % 2 === 0) {
console.log(numbers[i] * 2)
    } if ( i % 2 !== 0) {
        console.log(numbers[i] * 3)
    }
}
console.log(numbers)

However; to complete the assignment log must say;
4, 8, 15, 87, 76 ];

My log after my best try says:
4 12 10 87 76

12 must be 8
10 must be 15

 

[Deleted member 2829]

Is the assignment actually clear to you ? The statement "multiply all the even and uneven numbers inside an array" seems equivalent to "multiply all the numbers in the array" - that could be one hell of a big number, especially when there's a trillion numbers in the array. I don't understand that second requirement anyway - either your loop works or it doesn't, regardless of the array size. And are you required to actually change the array or just print some output like you are doing ? Your final console.log(numbers) seems to suggest you do want to change them

Your loop is trying to multiplying the numbers by 2 or 3, depending whether they are odd or even. If the result for [2, 4, 5, 29, 38] is expected to be 4, 8, 15, 87, 76 then this seems to be what you need to do (despite the poorly stated assignment - good job they give you the answer). So why are you getting the wrong output ? Look again, you are testing the index if (i % 2 === 0) rather than the number at that index if (numbers[i] % 2 === 0)

So let's rewrite that :

const numbers = [2, 4, 5, 29, 38];
for ( let i = 0; i < numbers.length; i++ )
{
    if ( numbers[i] % 2 == 0)
    {
        numbers[i] *= 2
    }
    else
    {
        numbers[i] *= 3
    }
}
console.log(numbers)

Things you may notice:
1) We now test the number instead of the index
2) We use == instead of ===. There is no need to compare datatypes here, so no need to use ===
3) Using if-else instead of two if statements. The number is either even or odd.
4) Using *=, the multiply AND assignment operator
5) The array elements are is now being modified

 

[Developsom]

Is the assignment actually clear to you ? The statement "multiply all the even and uneven numbers inside an array" seems equivalent to "multiply all the numbers in the array" - that could be one hell of a big number, especially when there's a trillion numbers in the array. I don't understand that second requirement anyway - either your loop works or it doesn't, regardless of the array size. And are you required to actually change the array or just print some output like you are doing ? Your final console.log(numbers) seems to suggest you do want to change them

Your loop is trying to multiplying the numbers by 2 or 3, depending whether they are odd or even. If the result for [2, 4, 5, 29, 38] is expected to be 4, 8, 15, 87, 76 then this seems to be what you need to do (despite the poorly stated assignment - good job they give you the answer). So why are you getting the wrong output ? Look again, you are testing the index if (i % 2 === 0) rather than the number at that index if (numbers[i] % 2 === 0)

So let's rewrite that :

const numbers = [2, 4, 5, 29, 38];
for ( let i = 0; i < numbers.length; i++ )
{
    if ( numbers[i] % 2 == 0)
    {
        numbers[i] *= 2
    }
    else
    {
        numbers[i] *= 3
    }
}
console.log(numbers)

Things you may notice:
1) We now test the number instead of the index
2) We use == instead of ===. There is no need to compare datatypes here, so no need to use ===
3) Using if-else instead of two if statements. The number is either even or odd.
4) Using *=, the multiply AND assignment operator
5) The array elements are is now being modified

Thank you very much.
1)If I want to test something inside an array I always test the const instead of just the index.
4)I did not know about the multiply AND assignment. It was hard for me to place the * because webstorm kept telling me it needs an assignment.

Thank you

 

[Deleted member 2829]

1)If I want to test something inside an array I always test the const instead of just the index.

Not sure what you mean with "the const". I would say test the array element, not the index.

4)I did not know about the multiply AND assignment. It was hard for me to place the * because webstorm kept telling me it needs an assignment.

Not sure what your issue with webstorm is regarding the *.

What does amaze me is that JavaScript lets you modify the elements of an array that is defined as const. That is rather counter-intuitive I think... Unless someone can explain ?

 

[Developsom]

Not sure what you mean with "the const". I would say test the array element, not the index.

Not sure what your issue with webstorm is regarding the *.

What does amaze me is that JavaScript lets you modify the elements of an array that is defined as const. That is rather counter-intuitive I think... Unless someone can explain ?

Yes ! I can explain; sorry for my late reply.

Basically it is being 'overwritten' and not 'modified'.

So you can not add completely new array/object but you CAN overwrite existing values.

 

[Deleted member 2829]

Basically it is being 'overwritten' and not 'modified'.

So you can not add completely new array/object but you CAN overwrite existing values.

There must be a very fine line between overwritten and modified... I for one don't see it 😀
But yes, it seems like in a const array you can modify all the elements, just not add or delete elements. So much for the concept of being constant ! ? Ah well, there is probably a good reason for this being so.

But more importantly, is your problem solved now ?

 

[Developsom]

There must be a very fine line between overwritten and modified... I for one don't see it 😀
But yes, it seems like in a const array you can modify all the elements, just not add or delete elements. So much for the concept of being constant ! ? Ah well, there is probably a good reason for this being so.

But more importantly, is your problem solved now ?

Yes, that's exactly what I mean by 'overwriting'.

Yes the the problem is solved, thank you !