Hello. I have an html audio control on my site. The .mp3 files it takes as it's source are in a folder called Samples. This has always worked fine in my old Classic ASP site, but I am now re-writing the site in PHP and I have found that the audio control will only work if my .mp3 files are in the root directory. I have a lot of them and I dont really want them scattered all over the root directory, it's much neater to have them all together in a folder. How can I get this to work? or if it wont, is there another solution? Many thanks for any help.
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HTML html audio control cant find .mp3 in folder
- Thread starter Wes.
- Start date
Hey and welcome
most likely you have a directory issue within the code but i really need to see your code before i can help
, if you could upload your code using BB Code then i would be happy to take alook Hi, thanks for your reply. The .mp3 files are in a folder called "Samples". The page which displays the Audio Control is in the root directory. It displays a list of pieces of music and the invitation to listen to each one.
$row["Listen"] contains "/Samples/some_audio_file_name.mp3" according to which of the audio files apply to the particular item in the list.
The code works fine if I copy an audio file to the root directory and change $SamplesPath accordingly, but otherwise it displays in a 'greyed out' state and refuses to work.
The code which calls the Audio Control is as follows:-
Many thanks for any help you can give me.
$row["Listen"] contains "/Samples/some_audio_file_name.mp3" according to which of the audio files apply to the particular item in the list.
The code works fine if I copy an audio file to the root directory and change $SamplesPath accordingly, but otherwise it displays in a 'greyed out' state and refuses to work.
The code which calls the Audio Control is as follows:-
PHP:
$SamplesPath = ("www.fmtest.info" . $row["Listen"]); //define the path to the samples folder
echo "<tr>";
echo "<td Style='line-height: 45px; border: 0px solid black;' colspan='2' >";
echo "<img src='images/Listen.jpg' WIDTH='35' HEIGHT='50' ALT='Listen' TITLE='Listen' ALIGN='left' >";
echo " Listen to this music";
echo "</td>";
echo "<td Style='line-height: 5px; text-align: left; border: 0px solid black;' colspan='2'>";
?>
<audio controls style="width: 500px; z-index:0;">
<source src=" . $SamplesPath . " type='audio/mpeg'>
</audio>
<?php
echo "</td>";
echo "</tr>";Many thanks for any help you can give me.
Last edited by a moderator:
i cant really help too much as everything is in a database unless you can send it all over, so this may take a while
looking at your code,
is outside of a php tag so you need to do
that should now work
looking at your code,
HTML:
<audio controls style="width: 500px; z-index:0;">
<source src=" . $SamplesPath . " type='audio/mpeg'>
</audio>is outside of a php tag so you need to do
HTML:
<audio controls style="width: 500px; z-index:0;">
<source src="<?PHP echo $SamplesPath; ?>" type='audio/mpeg'>
</audio>that should now work
Ah yes I see what I've done there, used a php variable in a line of html ☹️ however I'm sorry but it still doesn't work. Could you clarify a couple of things?
1. I've got an alert telling me I should have put the code in the Code Editor. How do I do that?
and
2. What do you mean by "i cant really help too much as everything is in a database"
Cheers.
1. I've got an alert telling me I should have put the code in the Code Editor. How do I do that?
and
2. What do you mean by "i cant really help too much as everything is in a database"
Cheers.
Click that icon and then put your code in there
Usually, i would say send me over your code and ill have a look, the issue is where your calling from a database I cannot see what's happening.
Add this code and paste the output here
Usually, i would say send me over your code and ill have a look, the issue is where your calling from a database I cannot see what's happening.
Add this code and paste the output here
Code:
echo $SamplesPath;
echo $row["Listen"];did you just run the code and echo them?
add echo $SamplesPath; to the end of the script and what is thats output.
Great to hear you solved it i thought it would be something simple thats why i was getting you to echo the outputs as i checked your code and it was fine
If you need any more help, just reach out
i thought it would be something simple thats why i was getting you to echo the outputs as i checked your code and it was fine If you need any more help, just reach out
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