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C++ Knight's Tour

SimonFudaxian

New Coder
Knight's Closed Tour (a classic programming problem)
C++:
// Moves are made by the lowest accessility points (1 - 8)
int mStart[64], mEnd[64], mIndex[336];
int mRate[] = {2,3,4,4,4,4,3,2,3,4,6,6,6,6,4,3,4,6,8,8,8,8,6,4,4,6,8,8,8,8,6,4,4,6,8,8,8,8,
               6,4,4,6,8,8,8,8,6,4,3,4,6,6,6,6,4,3,2,3,4,4,4,4,3,2};
string mNum[64],nNum[] = {" 0"," 1"," 2"," 3"," 4"," 5"," 6"," 7"," 8"," 9","10","11","12",
         "13","14","15","16","17","18","19","20","21","22","23","24","25","26","27","28",
         "29","30","31","32","33","34","35","36","37","38","39","40","41","42","43","44",
         "45","46","47","48","49","50","51","52","53","54","55","56","57","58","59","60",
         "61","62","63","64"};
void Tour2()
{
  int k1, k2, n1, aMove,aStart, aEnd, aMin;
  string x1, aTour;
  char c1[64];
  aMove = 0; // Use 0-63 to represent the chessboard. Knight's first move is cell 0
  aTour = mNum[aMove];
  for (k2 = 2; k2 <= 64; k2++)
        {
      mRate[aMove] = 99; aMin = 9; // When a move is picked, the cell is assign 99 points.
          aStart = mStart[aMove]; aEnd = mEnd[aMove];
          for (k1 = aStart; k1 <= aEnd; k1++)
                {
           n1 = mIndex[k1]; mRate[n1] = mRate[n1] - 1;
                   if (aMin > mRate[n1])
                        {
                          aMin = mRate[n1]; aMove = n1;    //Check out which one is the smallest
                        }
                         }
                   aTour = aTour + mNum[aMove];
               }
        }
              // The Knight's Closed Tour is completed.
        cout << "Knight's Closed Tour (classic programming problem)" << endl;
       cout << "ASCII characters representing Arabic Numbers" << endl;
    
       cout << aTour << endl;
       cout << "The first four moves: 0:4> = 0,10,4,13." << endl << endl;
       string aShow[64];
       aTour.copy(c1,64);
       x1 = ""; // Format the 64 moves.
       for (k1 = 0; k1 <= 63; k1++)
             {
               n1 = int(c1[k1]) - 48;
           aShow[n1] = nNum[k1 + 1] + " ";
          }
      x1 = "";
      for (k1 = 0; k1 <= 63; k1++)
            x1 = x1 + aShow[k1];
      n1 = 0;
      for (k2 = 1; k2 <= 8; k2++)
            {
              cout << "  " << x1.substr(n1,24) << endl;
              n1 = n1 + 24;
        }
}
 
 void SetUp1()
 { 
   int k1, k2, n1, n2, n3, aCount = -1, aFilter[64], bFilter[120];
   int aStep[] = {12,-21,-19,21,-12,-8,19,8}; // Use this to build a 2D structure to get in-bound moves only
   string x1, x2;
   for (k1 = 0; k1 <= 63; k1++) //Format Arabic
        mNum[k1] = char(k1+48);
   for (k1 = 0; k1 <= 119; k1++) //Set up a filter. 64 represents nothing
        bFilter[k1] = 64;
   for (k2 = 21; k2 <= 91; k2+= 10) // Set up a 2-D structure for filtering
         {
       for (k1 = k2; k1<= k2 + 7; k1++)
            {
          aCount = aCount + 1;
                  aFilter[aCount] = k1;
                  bFilter[k1] = aCount;
                }
         }
   aCount = -1;
   for (k2 = 0; k2<= 63; k2++)
         {
       n1 = aFilter[k2];
           mStart[k2] = aCount + 1;
           for (k1 = 0; k1<= 7; k1++)
                 {
           n2 = n1 + aStep[k1];
                   n3 = bFilter[n2];
                   if (n3 != 64)
                        {
              aCount = aCount + 1;
                          mIndex[aCount] = n3; //Pick up in-bound moves only
                        }
                 }
           mEnd[k2] = aCount; //mStart and mEnd for quick and easy retrieval of moves
         }
  }
 
Last edited by a moderator:
A program longer than 64 bytes, that prints a Knight's tour, is kind of pointless.

If you're going to hardcode every square's degree (what you call mRate) then you may as well hardcode the tour itself.

Besides, a tour is very easy to construct with pencil and paper.

Just my opinion.
 

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