hello everyone ..
i would really appriciate it if someone would help me with this question..
i upload here the code i wrote, its not really solving anything (i get an really odd outputs),but i would like that someone will explain to me what am i doing wrong ( even if its probably everything 🙁 )..
so the question is to write an efficiant function that turn the digites from right to left (the user choose the amount of spins he would want to do on a function )
i would really appriciate it if someone would help me with this question..
i upload here the code i wrote, its not really solving anything (i get an really odd outputs),but i would like that someone will explain to me what am i doing wrong ( even if its probably everything 🙁 )..
so the question is to write an efficiant function that turn the digites from right to left (the user choose the amount of spins he would want to do on a function )
C:
#include<stdio.h>
#include<math.h>
int rotateNumber(int number, int spins)
{
int reminder, answer = 0, num =0;
for (int i = spins;i >0; i--)
{
reminder = number % 10;
answer = reminder * (10 ^ (num-1)) + answer;
num--;
}
return answer;
}
int numberLength(int num)
{
int number = 0, spins = 0;
while (number != 0)
{
{
num = number / 10;
num++;
}
}
if (spins % num == 0)
{
printf("%d", number);
}
return number;
}
inputIntNonNegative()
{
int number = 0,spins=0;
scanf_s("%d", &number);
while (number < 0)
{
printf("Enter a positive number: ");
scanf_s("%d", &number);
}
return number;
return spins;
}
void main()
{
int number = 0, spins = 0, answer = 0;
printf("\nplease enter the number: ");
number = inputIntNonNegative();
printf("please enter the amount of spins: ");
spins = inputIntNonNegative();
answer = rotateNumber(number, spins);
printf("The number %d after %d spins is: %d\n", number, spins, answer);
}
