C Expression must have pointer-to-object type

[tom3141]

I have defined some variables. I have previously defined

#define SYS_LEN 50.0
#define N_CELLS ((int)SYS_LEN)

as well as

extern double *array_one

where I populate the array via

array_one[0] = 0.5*SYS_LEN
array_one[1] = 0.25*SYS_LEN

I then go onto define a further array within a function

void function(void)
{
int is, ix;
double X;
for (is = 0; is < MAX_VALUE; is++){
    for (ix = 0; ix < MAX_VALUE_TWO; ix++)
    {
    X[is] = 0.5 + (double)ix - array_one[is]
    }
}}

However I get an error stating 'expression must have pointer-to-object type'. Not too sure why this is, any help would be appreciated

Thank you

 

[Deleted member 2829]

You might consider posting the full code instead of just little snippets which seem to lack semicolons. Now we wonder what is the purpose of a function with no arguments and no return value which only manipulates some local variables ? And where exactly do you get that error ? I can see that this is wrong :

double X;
...
    X[is] = 0.5 + (double)ix - array_one[is]

but I'd expected another error message, such as X is not an array.