PHP posting chosen option to another page

[220061]

I'm not seeing what I'm doing wrong. so basically what I want is that users click the button and then the $row['name'] will be posted to another page. but for some reason I just can't get it to work?? can someone help me ?

    <?php
      $sql = "SELECT * FROM huizen";
      $stmt = $conn->prepare($sql);
      $stmt->execute();
      $result = $stmt->get_result();
      while ($row = mysqli_fetch_assoc($result)) {
          echo '       
          <div class="product">
          <form action="../reservation.php" method="POST">
            <h3 class="productname" id="naam" name="naam">'.$row['naam'].'</h3>
            <img src="../'.$row['img_dir'].'" alt="huis" style="width: 100%; height: 50%;">
              <p>'.$row['beschrijving'].'</p>
              <p class="price">'.$row['price'].'</p>
              <button class="addtocart" name="bestellen">Bestellen</button>
            </form>
          </div>';
      }
      ?>

this is the other page I want to show the naam from the first page ? what is going wrong?

 <h2>Reserveren <?php $_POST['naam'];?>

 

[Mutiny]

You need to have an actual form field to submit with your form. Change:

<h3 class="productname" id="naam" name="naam">'.$row['naam'].'</h3>

To:

<label>
    '.$row['naam'].'
    <input type="hidden" name="naam" value="'.$row['naam'].'" />
</label>

Also, you need to echo out the value when you retrieve it if you want to display it, so:

<h2>Reserveren <?php echo $_POST['naam'];?>