THE PROGRAM IS NOT RUNNING

[sxy]

#include <stdio.h>

int multiplication(int a,int b)
{
    int c;
    c=a*b;
    return c;
}

void main(void)
{
    int r;
    r = multiplication(2,8);
    printf(“%d”,r);
}

I should get 16
but it is not runing.
why?
thanks a lot

 

[BGB]

Because your code has no-ascii character. Change -

printf(“%d”,r);

to

printf("%d", r);

 

[Deleted member 2829]

That's what you get for copying and pasting code from random websites. I've been bitten by it several times. Depending on the font, it can be very hard to spot visually. Then again, the compiler (at least the Windows compiler) is very explicit what the problem is

C:\Users\Chris>cl t.c
Microsoft (R) C/C++ Optimizing Compiler Version 19.33.31629 for x86
Copyright (C) Microsoft Corporation.  All rights reserved.

t.c
t.c(14): error C3873: '0x201c': this character is not allowed as a first character of an identifier
t.c(14): error C2065: '“': undeclared identifier
t.c(14): error C3872: '0x201d': this character is not allowed in an identifier
t.c(14): error C2065: 'd”': undeclared identifier
t.c(14): warning C4047: 'function': 'const char *const ' differs in levels of indirection from 'int'
t.c(14): warning C4024: 'printf': different types for formal and actual parameter 1

so I do wonder why the question had to be posted in the first place.…