C# Binary -> Decimal Converter Outputting large numbers outside of reason...

[DolF1NN]

When I input a binary number into the string variable "binary" say "0000" it returns 720, the number seems to be based on how many characters are in the string Binary, and the number exponentially increases the more digits. I dont know why this is... Could someone help me out?

My code is:

using System;
                    
public class Program
{
    public static void Main()
    {
        string binary = "0000";
        int binaryLength = binary.Length;
        double binaryInt = 0;
        for(int i = binaryLength; i > 0; i--)
        {
            binaryInt += (binary[i - 1]) * (Math.Pow(2, binaryLength - i));
            Console.Write(binary[i - 1] + "  ");
            Console.WriteLine(Math.Pow(2, binaryLength - i) + "   ");
            
        }
        Console.WriteLine();
        Console.WriteLine(binaryInt);
    }
}

 

[ratwolf]

When I input a binary number into the string variable "binary" say "0000" it returns 720, the number seems to be based on how many characters are in the string Binary, and the number exponentially increases the more digits. I dont know why this is... Could someone help me out?

My code is:

using System;
               
public class Program
{
    public static void Main()
    {
        string binary = "0000";
        int binaryLength = binary.Length;
        double binaryInt = 0;
        for(int i = binaryLength; i > 0; i--)
        {
            binaryInt += (binary[i - 1]) * (Math.Pow(2, binaryLength - i));
            Console.Write(binary[i - 1] + "  ");
            Console.WriteLine(Math.Pow(2, binaryLength - i) + "   ");
       
        }
        Console.WriteLine();
        Console.WriteLine(binaryInt);
    }
}

You're seeing unexpected results because you're treating the characters in the binary string as their ASCII values, not actual binary digits.

Add:

// Get the binary digit character and convert it to its integer value (0 or 1)
int bit = binary[i - 1] - '0';

using System;

public class Program
{
    public static void Main()
    {
        string binary = "0000";
        int binaryLength = binary.Length;
        double binaryInt = 0;
        for(int i = binaryLength; i > 0; i--)
        {
            int bit = binary[i - 1] - '0';
            binaryInt += bit * Math.Pow(2, binaryLength - i);
            Console.Write(bit + "  ");
            Console.WriteLine(Math.Pow(2, binaryLength - i) + "   ");
        }
        Console.WriteLine();
        Console.WriteLine(binaryInt);
    }
}

 

[ratwolf]

You're seeing unexpected results because you're treating the characters in the binary string as their ASCII values, not actual binary digits.

Add:

// Get the binary digit character and convert it to its integer value (0 or 1)
int bit = binary[i - 1] - '0';

using System;

public class Program
{
    public static void Main()
    {
        string binary = "0000";
        int binaryLength = binary.Length;
        double binaryInt = 0;
        for(int i = binaryLength; i > 0; i--)
        {
            int bit = binary[i - 1] - '0';
            binaryInt += bit * Math.Pow(2, binaryLength - i);
            Console.Write(bit + "  ");
            Console.WriteLine(Math.Pow(2, binaryLength - i) + "   ");
        }
        Console.WriteLine();
        Console.WriteLine(binaryInt);
    }
}

or:

using System;

public class Program
{
    public static void Main()
    {
        string binary = "0000";
        int decimalValue = Convert.ToInt32(binary, 2);
        Console.WriteLine($"Binary: {binary}");
        Console.WriteLine($"Decimal: {decimalValue}");
    }
}