Python Confused about recursion in python-depth first search-:

[shivajikobardan]

# Python dictionary to act as an adjacency list
graph = {
  '7' : ['19','21', '14'],
  '19': ['1', '12', '31'],
  '21': [],
  '14': ['23', '6'],
  '1' : [],
  '12': [],
  '31': [],
  '23': [],
  '6' : []
}

visited = [] # List of visited nodes of graph.
def dfs(visited, graph, node):
    
    if node not in visited:
        visited.append(node)


    for neighbor in graph[node]:
        dfs(visited, graph, neighbor)
    print(node)

# Driver Code
print("Following is the Depth-First Search")
dfs(visited, graph, '7')
print("visited=",visited)

what I don't understand is how do once this program reaches to print(1) what happens next, it doesn't make any sense to me.
idk if I am stupid or what to not realize sth very trivial or idk.

I will try to explain what is my problem, step by step.
steps-:

1) dfs(visited,graph,7)

2)
7 not in visited.
visited=7
dfs(19)

3) 19 not in visited.
visited=7,19
dfs(1)

4) 1 not in visited
visited=7,19,1
1 has no neighbours.
print(1)

imo the code should stop now. Because there is no function call no nth. But in fact the code goes to

for neighbour in graph(node):
dfs(visited,graph,neighbour)
and starts with dfs(12). I don't understand this....How does it happen?

how can it go to for loop just like that?(source-:https://cscircles.cemc.uwaterloo.ca/visualize#mode=display)

even if it doesn't go to for loop, I can't make sense where it really goes. Can you please guide me about this issue?