JavaScript jquery unrecognized expression:

[stefan86]

Hello all, I have a Syntax error, unrecognized expression. I use a set of links to change to a div on the same page and sent a variable with it.


<a href="?taal=<?PHP echo $taal; ?>#Home">Voorpagina</a>
<a href="?taal=<?PHP echo $taal; ?>#Updates">Updates</a>
<a href="?taal=<?PHP echo $taal; ?>#About">Over mij</a>


$taal is the language the user choose, like NL, EN...

After the user clicks, get this in action:

$('a').click(function (e) { $('html, body').animate({ scrollTop: $($(this).attr('href')).offset().top}, 500); });


Everything works but I get the next error in my console:

Uncaught Error: Syntax error, unrecognized expression: ?taal=nl#Home
at Sizzle.error (jquery-3.6.0.js:1681:8)
at Sizzle.tokenize (jquery-3.6.0.js:2381:11)
at Sizzle.select (jquery-3.6.0.js:2842:20)
at Function.Sizzle [as find] (jquery-3.6.0.js:898:9)
at jQuery.fn.init.find (jquery-3.6.0.js:3099:11)
at new jQuery.fn.init (jquery-3.6.0.js:3209:32)
at jQuery (jquery-3.6.0.js:161:10)
at HTMLAnchorElement.<anonymous> (?taal=nl:175:24)
at HTMLAnchorElement.dispatch (jquery-3.6.0.js:5430:27)
at elemData.handle (jquery-3.6.0.js:5234:28)

How can I resolve this error? By the way, if I remove the <?PHP echo $taal; ?> variable in the links above (first code), the error is gone but I need that variable for further navigation.

Thanks in advance.

 

[Deleted member 2829]

I use a set of links to change to a div on the same page and sent a variable with it.

Changing to a local <div> is fine, but how do you envisage passing a variable with that ? Or rather, how should the div pick that value up ?
Assuming $taal is nl, your PHP lines result in this HTML :

<a href="?taal=nl#Home">Voorpagina</a>
<a href="?taal=nl#Updates">Updates</a>
<a href="?taal=nl#About">Over mij</a>

but those are not valid href's. This

<a href="#Home?taal=nl">Voorpagina</a>
<a href="#Updates?taal=nl">Updates</a>
<a href="#About?taal=nl">Over mij</a>

would make more sense, but I'm still not sure how the html is supposed to pick up that parameter. Why do you feel the need to pass it anyway ? You can ask PHP for it any time you need it.