Python Digit into number

[voldyy]

Hi, how can i change this code to work for two-digit numbers or three-digit number?

For now only work for single digit numbers, tried to change algorthm but didnt work.

def to_number(digits):
    result=digits[0]
    for el in digits[1:]:
        result=result*10
        result=result + el
    return result

Now the ouput is 2221 - i think is because of this line result=result + el
It has to output this:
input: [ 21, 12, 1]
output: 21121

 

[Coding4Fun]

I could be wrong but I think you are trying to get 23221 not 21121

def to_number(digits):
    result=digits[0]
    for el in digits:
        result=result*10
        result=result + el
    return result
  
x = to_number([21,12,1])
print(x)

#21 * 10 = 210 + 21 = 231
#231 * 10 = 2310 + 12 = 2322
#2322 * 10 = 23220 + 1 = 23221

The way you have it there its:

def to_number(digits):
    result=digits[0]
    for el in digits[1:]:
        print("our digit is {}".format(el))
        print("result is {}".format(result))
        result=result*10
        result=result + el
    return result
  
x = to_number([21,12,1])
print(x)

#21 * 10 = 210 + 12 = 222
#222 * 10 = 2220 + 1 = 2221

Output:
our digit is 12
result is 21
our digit is 1
result is 222
2221

 

[simong1993]

We need a few more answers as to what you are trying to do 😀

 

[voldyy]

We need a few more answers as to what you are trying to do 😀

another example: turn a list of digit into number
input [12,12,1]
output 12121

input:[21,34,7]
output: 21347

#for this one code work
input[5,4,3,0,2]
output 54302

 

[Coding4Fun]

Perhaps:

def to_number(digits):
    result = ''
    for el in digits:
        result = result + str(el)
    return int(result)
  
x = to_number([21,34,7])
print(x)

 

[menator01]

def to_number(digits):
     result = [str(digit) for digit in digits]
     result = ''.join(result)
     return int(result)

myinput = [21,12,1]
print(to_number(myinput))