PHP Unsure how to handle a string with mixed quotes

[dave0matic]

Hello!

I ran into this situation that I've never seen before and I'm rather at a loss on how to handle it

$s = "Based on an image I found. Hopefully it says, "Backup, I'll cut you!"";

This will NOT pass the syntax check because of the mixed quotes in the string.

Even tried concatenating quotes to the beginning and end

$s = """ . "Based on an image I found. Hopefully it says, "Backup, I'll cut you!" . """;

So how does one use this? Still surprised that I haven't had this problem ever occur before!

Thank you for any help/tips/tricks!

Regards,

Dave

 

[TimB]

The simplest way is to just escape the quotes in the PHP variable
ie... $str = "Here is a quote that I like, \"Some quote here.\"";

 

[Ghost]

Hello!

I ran into this situation that I've never seen before and I'm rather at a loss on how to handle it

$s = "Based on an image I found. Hopefully it says, "Backup, I'll cut you!"";

This will NOT pass the syntax check because of the mixed quotes in the string.

Even tried concatenating quotes to the beginning and end

$s = """ . "Based on an image I found. Hopefully it says, "Backup, I'll cut you!" . """;

So how does one use this? Still surprised that I haven't had this problem ever occur before!

Thank you for any help/tips/tricks!

Regards,

Dave

Hey Dave, as TimB said above, you can use escapes (backslash) so the quotations are ignored and don't interfere.

$s = "Based on an image I found. Hopefully it says, \"Backup, I'll cut you!\"";
$s2 = 'Based on an image I found. Hopefully it says, "Backup, I\'ll cut you!"';

In my example, you can see that $s2 shows you that you can use the single quotes for the string and just escape the single quote in I'll, or in the first example we just escape the double quotes!